U^4+13u^2+40=0

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Solution for U^4+13u^2+40=0 equation: 



^4+13U^2+40=0

We add all the numbers together, and all the variables

13U^2=0

a = 13; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·13·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$U=\frac{-b}{2a}=\frac{0}{26}=0$

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